Ans is 198.47.32.0
as 198.47.34.31 is destination address and 255.255.224.0 is subnet mask and when we apply Bitwise AND operation on 34 and 31 part of destination address with 224 and 0 we get 32(3rd octet) and 0(last octet) respectively.......
Correct me If I'm wrong.....:-)