Consider sending a file of 800,000 bits from Host A to Host B

Question

.Suppose the flie is send continuously as one large message calculate the total time taken to send the file.

PROPAGATION DELAY = 0.8 X 10^-4 SEC

BANDWIDTH DELAY = 160 SECONDS

DISTANCE FROM A TO B HOST IS 20 KMS

DIRECT LINK OF SPEED=2MBPS

Answer 1

Given , propogation delay between hosts  =  0.8 * 10^-4  s

bandwidth delay  =   160 s

Now we know 

Transmission delay to place the data on the channel = Data size / Data rate of the channel

                                                                             = 8,00,000 bits / 2 MBPS

                                                                             = 1,00,000 bytes / 2 * 10⁶ BPS [In network unit system 1 M = 10⁶]

                                                                             =  5,00,00 / 2 * 10⁶ s

                                                                             =  2.5 * 10^-2 s

Therefore ,

Total delay   =  160 + 0.8 * 10^-4  + 2.5 * 10^-2 s

                   =   160000 + 0.08 + 25 ms

                   =   160025.08 ms

Comments

transmission dealy is 50ms.. and what is bandwidth delay?