Given Set $A= {2, 3, 4, 5}$ and Set $B= { 11, 12, 13, 14, 15}$, two numbers are randomly selected, one from each set. What is the probability that the sum of the two numbers equals $16$?
option A because total combinations are $5\times 4=20$ and out of $20$ we have only $4$ combinations which have sum $16$
@Lakshman Patel RJIT
(2,14) (14,2) (3.13) (13,3) (4.12) (12,4) (5,11) (11,5)
This will also be correct
8 / 40 ==>0.2
option A
probability =Number of favorable case/total case
The favorable cases are:-
2,14 3.13 4.12 5,11
4C1=4
total case =A number selected from set A * A number selected from set B
4C1*5C1=20
probability =Number of favorable case/total case=4/20=0.20