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Given Set $A= {2, 3, 4, 5}$ and Set $B= { 11, 12, 13, 14, 15}$, two numbers are randomly selected, one from each set. What is the probability that the sum of the two numbers equals $16$?

  1. $0.20$
  2. $0.25$
  3. $0.30$
  4. $0.33$
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Best answer
17 votes
17 votes

option A because total combinations are $5\times 4=20$ and out of $20$ we have only $4$ combinations which have sum $16$

  1. $2,14$
  2. $3.13$
  3. $4.12$
  4. $5,11$
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2 votes
2 votes

option A

probability =Number of favorable case/total case

The favorable cases are:-

2,14
3.13
4.12
5,11 

4C1=4

total case =A number selected from set A * A number selected from set B

  4C1*5C1=20 

probability =Number of favorable case/total case=4/20=0.20

1 votes
1 votes
After choosing an element from A, there is only one element in B out of 5 elements that makes sum 16.

So, 1/5 = 0.2
0 votes
0 votes
Solution: A
The total number of pairs possible is 20(with 1 element from A and 1 element from B). The pairs which sum to 16 are 4nos, that are (2,14)(3,13)(4,12)(5,11). So 4/20 =0.20
Answer:

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