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When say that with n vertices there are total 2^(n(n-1)/2) connected/disconnected graph possible, in this case we are assuming that vertices are labelled, right??

 

Is there any formula to count number of connected/disconnected graphs possible with n unlabeled vertices?
asked in Graph Theory by Veteran (16.9k points) | 125 views

1 Answer

–2 votes
The # of labeled undirected graphs : 2^(n(n-1)/2)

The # of labelled directed graphs : 2^(n(n-1))
answered by Active (1.7k points)
edited by
With 3 unlabeled nodes possible undirected graphs are 4, but your formula gives 8/6 how?


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