Four branches of a company are located at $M$, $N$, $O$ and $P$. $M$ is north of $N$ at a distance of $4 km$; $P$ is south of $O$ at a distance of $2$ $km$; $N$ is southeast of O by $1 km$. What is the distance between $M$ and $P$ in $km$?
$a=\dfrac{1}{\sqrt{2}}$
$x=\sqrt{[4+(2-a)]^{2}+a^2}$
Solving we get x = 5.34.
Correct Answer: $A$
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Hence, Option A
Just giving more details to Accepted answer.