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Four branches of a company are located at $\text{M, N, O}$ and $\text{P.  M}$ is north of $\text{N}$ at a distance of $4\;\text{km; P}$ is south of $\text{O}$ at a distance of $2\;\text{km; N}$ is southeast of $\text{O}$ by $1\;\text{km}$. What is the distance between $\text{M}$ and $\text{P}$ in $\text{km}$?

  1. $5.34$
  2. $6.74$
  3. $28.5$
  4. $45.49$
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6 Answers

Best answer
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$a=\dfrac{1}{\sqrt{2}}$

$x=\sqrt{[4+(2-a)]^{2}+a^2}$

Solving we get $x = 5.34.$ 

Correct Answer: $A$

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For those who didn't understand previous explanations....

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For anything unclear, feel free to comment/message.

1

Hence, Option A

Answer:

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