Take $L1 = \Sigma *$ and let $x = aaabbb$ which belongs to L1
And let $L2 =\left \{ a^{n}b^{m} | n < m\right \}$
Hence, $aaabbbb$ belongs to L2 but $x$ is a substring of $aaabbbb$ which makes first statement false .
Let $L1 = a^n b* a* b^n$ and let $x = ab$ which belongs to L1
And Let $L2 = \left \{ a^n b^n c^m | n>m, n,m >=0 \right \}$
Hence, $ab$ belongs to L2 but $x$ is a substring of $ab$ which makes second statement also false .
Then how the answer is B).