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The maximum no that can be represented in binary using 126 bits =  11....(126 times)

= 2126 - 1

So to find number of digits in equivalent decimal notation , we do :

2126 - 1 = 10x

⇒x = Ceil(log(2126 - 1))

⇒x = Ceil (37.93)

⇒x = 38

Hence number of digits required to represent any 126 bit binary number in decimal is 38 digits.

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