52 votes 52 votes Consider a $4$-bit Johnson counter with an initial value of $0000.$ The counting sequence of this counter is $0, 1, 3, 7, 15, 14, 12, 8, 0$ $0, 1, 3, 5, 7, 9, 11, 13, 15, 0$ $0, 2, 4, 6, 8, 10, 12, 14, 0$ $0, 8, 12, 14, 15, 7, 3, 1, 0$ Digital Logic gatecse-2015-set1 digital-logic digital-counter easy + – makhdoom ghaya asked Feb 12, 2015 • edited Jun 21, 2021 by Lakshman Bhaiya makhdoom ghaya 20.8k views answer comment Share Follow See all 8 Comments See all 8 8 Comments reply Show 5 previous comments Nitesh Singh 2 commented Sep 20, 2019 reply Follow Share already seen their comments, referred books, NPTEL video lecture then saying it is an ambiguous question. There is indeed no restriction on the assignment of LSB & MSB. 1 votes 1 votes Obafgkme commented Sep 26, 2019 reply Follow Share @Nitesh Singh 2 see the dates below their comments, references are given in 2018 and their comments pertaining to "ambiguity" in question are of 2015.... 0 votes 0 votes Ray Tomlinson commented Jan 21 reply Follow Share We Not need to solve this question by making entire diagram with JK flip flop it is very time consuming just solve like below answwer last image https://gateoverflow.in/8219/gate-cse-2015-set-1-question-20?show=420352#a420352 0 votes 0 votes Please log in or register to add a comment.
4 votes 4 votes Johnson counter /twisted ring counter :- "N" bit then there will be "2N" states Option B easily eliminated as it has 9 state form rest we will have to check out. Answer :- D Prateek kumar answered Dec 23, 2017 Prateek kumar comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Structure: It consists of 4 flip-flops connected in a ring, with the inverted output of the last flip-flop feeding back to the input of the first flip-flop. Initial State: Starts with all flip-flops at $0 (0000)$. Counting: With each clock pulse, the bits shift one position to the right. The inverted output of the last flip-flop determines the new bit shifted into the first flip-flop. Counting Sequence: $0000$ (initial state) $1000$ (inverted $0$ from last flip-flop shifts in) $1100$ $1110$ $1111$ $0111$ (inverted $1$ from last flip-flop shifts in) $0011$ $0001$ $0000$ (repeats) rajveer43 answered Jan 12 rajveer43 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Straight Ring Counter. there are 4 states in a 4-bit Ring Counter. Johnson Counter (Twisted Ring Counter) So answer is option D Reference : Ring Counter in Digital Logic - GeeksforGeeks Ray Tomlinson answered Jan 21 Ray Tomlinson comment Share Follow See all 0 reply Please log in or register to add a comment.