here , short cut to this question
by watching figure u can guess that it's not distributive lattice, becoz for q there is 2 complement so , it cant satisfy distributive property , therefore, probability cant be 1 , so option (a) is wrong
now if u apply distributive property for any 3 elements which are in straight line they will satisfy the distributive property , it concludes that its probability cant be 0, therefore option (b) is wrong
now no of possible distributive equation will be 5*5*5=125 because repetition is allowed here. since in above line, i hav proved that elements in straight line will follow the distributive prop then no of possible distributive with 3 element is 3*3*3=27 (since repeatition is allowed , u might ask question that there are 5 elements then why 3 ? since we have to fix 2 as universal lower bound and upper bound ) so 27/125 is greater than 1/5
so d option is correct