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Let $f(A,B) = A'+B$. Simplified expression for function $f(f(x+y, y), z)$ is

1. $x' + z$
2. $xyz$
3. $xy' + z$
4. None of the above
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0
C is a correct option

$f(f(x+y, y), z) = f((x+y)' +y), z)$

$=((x+y)' + y)' + z$

$= (x+y).y' + z (\because (a+b)' = a'.b')$

$= xy' + z$
selected
ans c)