Seek time $ =4ms$
In 60 seconds 1000 rotations.
Rotation Time$ = (60 / 10000) = 6 ms $ (Time to read one Track)
Rotational latency$ = (1 / 2 ) * 6ms = 3ms $
Transfer time = No. of tracks * time to read one track
$= $(Sectors in file/Sectors in one track) * (Time to read one track)
$= (2000/600)*6
= 20$ ms
total time needed to read the entire file is:
$= 2000*(4+3) + 20
= 8000 + 6000 + 20 = 14020$ ms
So, correct answer is 14020.