If we talk on the basis of Redundancy hierarch , then BCNF(according to gate Syllabi) is on TOP , means if a relationis in BCNF then it is free from redundancy.
As the given Ques says that table is already in 3NF , so there should be no Partial dependency and no transitive dependency.(rule of 3 NF).
Now, for a relation to be in BCNF we must satisfy:
- X → Y is a trivial functional dependency (Y ⊆ X)
- X is a super key for schema R.
So the answer should be B,C,D
because Prime attributes are the attributes of the candidate key which defines the uniqueness (Eg: SSN number in a employee database) , they are not candidate key nor form a superkey.
Note: If i am wrong then some moderator or required people can correct me.