since,it is given that first card has to be the club.so we can choose it in 13 ways.(it can also be a queen of club because there is no restriction on first card to be a queen)
now,for second card,it is mentioned that it should not be queen(but it can be a club).
1)when second card is non-queen of club-there are 12 non queen cards from 13 club cards.
2) when second card is non-queen of any suit but not club -there are 52 -13(for clubs) - 3(queens) =36 cards to choose from.
hence,probability = 13C1 * 12C1 /52C2 + 13C1 * 36C1/ 52C2.
@vaishali,am i correct??please do let me know the answer