10,447 views
22 votes
22 votes

Four fair coins are tossed simultaneously. The probability that at least one head and one tail turn up is

  1. $\frac{1}{16}$
  2. $\frac{1}{8}$
  3. $\frac{7}{8}$
  4. $\frac{15}{16}$

5 Answers

–1 votes
–1 votes
probability of getting head=p=1/2;

by the formula p(x)=nCx*P^xq^(n-x)

p(atleast one tail)=p(x>=1)==1-p(x<1)=4C0*(1/2)^4=1-1/16=15/16

p(atleast one head)=p(x>=1)==1-p(x<1)=4C0*(1/2)^4=1-1/16=15/16

so

P(head&tail)=15/16*15/16=7/8
Answer:

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