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The number of ways in which $5\; A's, 5\; B's$ and $5\; C's$ can be arranged in a row is:

  1. $15!/(5!)^{3}$
  2. $15!$
  3. $\left(\frac{15}{5}\right)$
  4. $15!(5!3!)$.
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2 Answers

Best answer
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11 votes

(A) Use permutation with repetitions formula as we have to arrange $15$ elements where $5$ each are identical. 

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