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In the network $200.10.11.144/27$, the $\text{fourth}$ octet (in decimal) of the last $\text{IP}$ address of the network which can be assigned to a host is _______.
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The below image explains why 158 should be answer.

As last and first value cant be used to assign to a host

we always assign $2^{hid}$-2 

 

The last bit is 0 as if it were 1, it would have been directed broadcast address of the Network

 

Answer:

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