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Find the minimum product of sums of the following expression

$f=ABC + \bar{A}\bar{B}\bar{C}$
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Minimal POS

$f=(\bar{A} + B) (A+\bar{C}) (\bar{B}+C)$

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There are many such pos possible given is one of the Possible POS.
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sir i am getting (A+B') (B+C') (B+A') ..i dont what is going wrong with me please help sir ..!
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you put AB on the top of the k-map and c is below..and here is opposite in above answer.
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@air1ankit in pos we will take 1 in complement and 0 as normal while in sop we take 1 as normal and 0 as a complemented

check are you correct here.

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@Anu007

Given is the minimal POS!
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Yes it is minimal POS
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there is a typo in the solution, it's 0 at A'BC, but it is 1 in the above K-map.

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Here there are no essential prime implicants. So many POS are possible.
In this minimization given expression is in SOP (Sum of product form) but in question POS form minimization asked so

Firstly We have to make K-map according to SOP form for SOP form entry is 1 but for POS it is 0 ,we can make remaining cells zero in this way we can do minimization easily
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