Aptitude

Question

A with the help of a son can do a work in 10days . They start together and after 6 days his son left the work . Then remaining work will be done by A in 8 days . Then A alone would do work in how many days ?

verify please :)

Comments

is it 20 days??

Answer 1

Let A's son is B.

Let A does x work in 1 day.

and B does y work in 1 day.

Total work in 1 day = x+y;

Total work = Total work in 10 days by A+B = 10(x+y)

6 days both's (A+B) work + 8 days A's work = Total work

=> 6(x+y) + 8x = 10(x+y)

=> 14x +6y = 10x + 10y

=> x=y;

Total work = 10(x+y) = 20x

So, A will do the work in 20 Days.