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A disk unit has $24$ recording surfaces and a total of $14,000$ cylinders. There is an average of $400$ sectors per track. Each sector contains $512$ bytes of data.

What are the maximum number of bytes that can be stored in this unit?

  1. $67.80 * 10^9$ B
  2. $68.90 * 10^7$ B 
  3. $68.80 * 10^9$ B   
  4. $69.87 * 10^9$ B
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Given,

  1. Number of surfaces = 24
  2. Number of cylinders = 14,000 ( think it like total number of tracks )
  3. sectors per track = 400 
  4. Data density or Each sector contains  data = 512 Bytes 

Total capacity of the disk = Total number of tracks *  Number of sectors per track *  data in each sector * Number of surface 

=  14000 * 400 * 512 * 24

= 68.80 * 109 Bytes

Then maximum number of bytes that can be stored on this disk is = 68.80 * 109 Bytes.

Which match with option C .

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3 Comments

@ bikram veteran

 

plz explain ur answer
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@Aman Agrawal  

Total capacity of the disk is = Total number of tracks *  Number of sectors per track *  data in each sector * Number of surface 

see my answer now ..

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@ Bikram

thank you sir
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