0 votes 0 votes A disk has $20$ sectors per track. Assume there are $512$ bytes per sector. What is the data transfer rate (in bytes per second) at a rotational speed of $7200$ rpm? $1.26 * 10^8$ bytes/second $1.58 * 10^6$ bytes/second $1.318 * 10^5$ bytes/second $1.2288 * 10^6$ bytes/second CO and Architecture tbb-coa-1 co-and-architecture operating-system disk + – Bikram asked Nov 25, 2016 • retagged Sep 14, 2020 by ajaysoni1924 Bikram 389 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 0 votes 0 votes The data transfer rate is (20 * 512 * 7200)/60 = 1. 2288 * 10^6 bytes/second Bikram answered Nov 25, 2016 • selected Aug 26, 2019 by Bikram Bikram comment Share Follow See all 0 reply Please log in or register to add a comment.