Approach:
1. you can easily see, M->c and N->c will reduce and they will come into the same state so, they will lead to conflict and for SLR(1), we need to find the follow of M and N then we got the RR conflict.so, not SLR(1) => not LR(0) also.
2. now, draw LR(1) canonical collection you will find no conflicts but For LALR(1), by merging the states with same productions but different lookaheads you will get the RR conflict and they are due to M and N productions.
so,LR(1) but Not LALR(1)
ANSWER : (A)
additional note: CLR(1) is same term for LR(1).