1 votes 1 votes If $r1$ ,$r2$ and $r3$ are the accepting powers of DFA, NFA and NFA with Epsilon - moves, then ____________. $r1=r2=r3$ $r1 < r2 = r3$ $r1 = r2 < r3$ $r1$ not equal to $r2$ not equal to $r3$ Theory of Computation tbb-toc-1 + – Bikram asked Nov 26, 2016 • edited Aug 20, 2019 by Counsellor Bikram 297 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes DFA, NFA and ∈-NFA all have same powers! Hence (A) is answer! Vijay Thakur answered Jan 29, 2017 • selected Jan 29, 2017 by Bikram Vijay Thakur comment Share Follow See all 0 reply Please log in or register to add a comment.