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IP address of a particular class B host is $152.45.32.14$, what is the broadcast address of the subnet if the subnet mask is $255.255.240.0$?

  1. $152.45.47.255$
  2. $152.45.255.255$
  3. $152.45.53.14$
  4. $152.45.47.256$
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IP address of a particular class B host is 152.45.32.14, 16 bits for network part and 16 bits for host part .

need to calculate the broadcast address  of the subnet if the subnet mask is 255.255.240.0 

class B so N N H H , mask is 255.255.240.0  now 240 = 128 + 64 + 32 + 16 ( 2nd octet) 

128  64   32  16   8  4  2  1

 1    1     1     1   0  0   0  0

now turn / flip all 0 into 1 in both 1st and 2nd octet  and it become  1111 means 1 + 2 +4+8 = 15 in 2nd octet and in 1st octet 1111 1111 

now add 15 with 32 ( from ip address host 2nd octet) and it becomes 15 + 32 =  47

so  the broadcast address of  host  152.45.32.14 is  152.45.47.255

152.45.47.255 is option A hence it is the answer.

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