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An organization with a class C IP address of $195.37.5.0$ wish to divide the network into different sub networks, the subnet mask is 255.255.255.192. Which one among these is not a broadcast address in any of the sub network?

1. $195.37.5.127$
2. $195.37.5.191$
3. $195.37.5.31$
4. $195.37.5.255$

Can anyone explain how it is option (c)?

as subnet mask is 192 which is 11 000 000 so 2 bits we take for subnet bits from HID and total 4 subnets 2^2=4 are there and first subnet 00 second subnet 01 third subnet 10 and fourth subnet 11 .

last octet ::: 63(00) , 127(01), 191(10)  , and 255(11) for 195.37.5.127,    195.37.5.191,    195.37.5.255,     195.37.5.63 broadcast addresses possible  for 4 subnets  .

As given option c says 31 so c) is not broadcast address.

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I think there is problem with the test, My wrong answer it says right. Problem with lot of question please check @Bikram

Test name : Computer Networks-12

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