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There are 16bits in NID and 16bits in HID  in Class B network. 

Now 248 in binary is  11111 000

5 number of  1  in HID part

So $2^5 = 32$ total subnets are there .

http://www.ietf.org/rfc/rfc1878.txt
 

Hence number of subnets are 32.

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