2 votes 2 votes When simplified with Boolean Algebra, $(x + y)(x + z)$ simplifies to: $x$ $x + x(y + z)$ $x(1 + yz)$ $x + yz$ Digital Logic tbb-digital-logic-2 + – Bikram asked Nov 26, 2016 edited Aug 19, 2019 by Counsellor Bikram 247 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply Praveen Saini commented Dec 1, 2016 reply Follow Share x+yz 0 votes 0 votes air1ankit commented Aug 26, 2017 reply Follow Share explain please i am getting B 0 votes 0 votes Praveen Saini commented Aug 28, 2017 reply Follow Share paste your solution, I think you are doing some error 0 votes 0 votes Please log in or register to add a comment.
Best answer 2 votes 2 votes Given that $(x+y)(x+z)$ $\implies x\cdot x + x\cdot z + y\cdot x + y\cdot z$ $\implies x + xz + xy + yz$ $\implies x(1+z+y) + yz$ $\implies x\cdot 1 + yz$ $[\because1+X = 1]$ $\implies x +yz$ Lakshman Bhaiya answered Aug 18, 2019 selected Aug 18, 2019 by Bikram Lakshman Bhaiya comment Share Follow See all 0 reply Please log in or register to add a comment.