edited by
487 views
3 votes
3 votes

Convert the following $(734 )_8 =  ( \dots )_{16}$

  1. $C \ 1 \ D$
  2. $D \ C \ 1$
  3. $1 \ C \ D$
  4. $1 \ D \ C$
edited by

1 Answer

Best answer
2 votes
2 votes
$(734)_{8}=(...)_{16}$

First Convert Octal to Binary.

$8=2^{3}\implies$Write $3$-bit binary number for each digit.

$(734)_{8}=(111\:011\:100)_{2}$

Now we know that $2^{4}=16\implies$ Make a group of $4$-bit from LSB to MSB , and at MSB we can add zeros if required. And write the hexadecimal number from each group of $4$-bit binary number.

$(111\:011\:100)_{2} = (0001\:1101\:1100)_{2}=(1\:D\:C)_{16}$.

$\implies$ Hexadecimal number representation are follows this$:0,1,2,3,4,5,6,7,8,9,A(10),B(11),C(12),D(13),E(14),F(15)$

So,the correct answer is $(D)$.
selected by
Answer:

Related questions

2 votes
2 votes
1 answer
1
Bikram asked Nov 26, 2016
929 views
The excess $3$ code of decimal number $26$ is:$0100 1001$$01011001$$1000 1001$$01001101$
3 votes
3 votes
1 answer
2
Bikram asked Nov 26, 2016
272 views
$1$’s complement representation of decimal number of -$17$ by using $8$ bit representation is:$1110 \ 1110$$1101 \ 1101$$1100 \ 1100$$0001 \ 0001$
3 votes
3 votes
1 answer
3
Bikram asked Nov 26, 2016
2,859 views
If signed numbers are used in binary arithmetic, then which one of the following notations would have unique representation for zero?Sign-magnitude$1$’s complement$2$�...