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The lowest frequency in kHz, if a 6 MHz clock frequency is applied to a cascaded counter of modulus 2 counter and modulus 3 counter are ________.

is it correct ?

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Yes in case of cascading counter which is nothing but an standard asynchronous counter u can multiply individual mod values to get resultant mod value..

So  let us see how it works as well..Here after the input signal goes through 1st counter which is a mod 2 counter , so f1 = finp / 2

Now this output works as an input signal for 2nd flip flop of counter which is mod 3

So

          fout   =  f1 / 3

==>    fout   =  finput / 6

So net result is that output frequency gets divided by 6 w.r.t input frequency.

Thus this is nothing but the mod value of counter..

Hence output frequency here =  6 MHz / 6

                                           =  1 MHz

As a shortcut , if u r given 2 counters each of mod value m and n then frequency gets divided by mn as a whole..

edited by

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