Number of ways $ = $ Total $-$ not possible cases
Number of ways $ = \binom{11}{4} - \left[\binom{6}{0}\times\binom{5}{4} + \binom{6}{1}\binom{5}{3}\right]$
Number of ways $ = 330 - 65 = 265$
$$\textbf{(OR)}$$
$\text{Atleast '2' means 2 (or) more $(\geq 2)$.}$
Number of ways $ = \binom{6}{2} \times \binom{5}{2} + \binom{6}{3} \times \binom{5}{1} + \binom{6}{4} \times \binom{5}{0} = 265$
So, the correct answer is $(C).$