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There are $5$ hotels on a road. If $4$ men go into the hotel at $11$ am, then the probability that each go into a different hotel is ______.
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Total ways to check in to hotels $ = 5^4$

Ways in which they go in different hotels $ = \binom 5 4*4!$

Required probability $= \frac{5*4*3*2}{5^4} = 0.192$
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