First of all we have to check the ER diagram carefully.In this we have :
A) Strong entity employee with eid as the key
B) Weak entity dependent with dob as the partial key
C) A multivalued attribute phoneno..
So we need to have 3 relations :
a) For employee with eid as key
b) For {dependent , has} with {eid,dob} as key with eid being identifier
c) For multivalued attribute phoneno..
So no of attributes which are non prime in employee = 2 [which are dob,ename]
no of attributes which are non prime in {dependent , has} = 1 [which is dname only]
Hence C) is the correct answer..