Here u should know about prime implicants and essential prime implicants..And one important point on that :
If all cells are covered by essential prime implicants , then to form an irredundant minimal expression then we have to use the essential prime implicants only and not consider the non essential ones..But in redundant expression we can do that which is also being asked in the question
So in light of the K Map which is given all are essential prime implicants except one which is in the centre so to form redundant expression we consider the central prime implicant of 4 cells which is a non essential prime implicant also.
As is clear from the K Map ,
No of essential prime implicants = 4
No of non essential prime implicants = 1
So no of terms in redundant SOP expression = 5
Hence clearly D) is the correct answer..