I think you are right @vishal. it should be None of these as 0 or 00 or 0* is not in lang unless it conatins one 1 and both grammer are producing it. so it should be none of these.

1 vote

So , 1 is mandatory in Regular expression ; and both of above grammar allows strings without 1 to be genearated.

So , I expected None of above to be answer. What Am I missing here ?

Consider for (A)

Production = A0 -> A1

A1-> 0

0 votes

Create NFA for the given expression and from that grammer is as follows:

replace A0 with S and A1 with A

S->0S | 1A

A -> 0A | 1A | epsilon

the above grammer doesn't match with option A and B

In the options A and B they have production rule A0 -> A1 (As mentioned by @vishal8492) which will produce string "0" which is not accepted by the regular expression.

So the answer would D.

replace A0 with S and A1 with A

S->0S | 1A

A -> 0A | 1A | epsilon

the above grammer doesn't match with option A and B

In the options A and B they have production rule A0 -> A1 (As mentioned by @vishal8492) which will produce string "0" which is not accepted by the regular expression.

So the answer would D.