Ace Test Series: Computer Networks - Tcp

Question

Can someone explain what this question means?

Answer 1

I got the answer. But still didn't fully understand the statement about identification number.

 

Anyways...here is the answer.

(2^16 * (1024*8))/ Bandwidth = 120 sec

Solve this....you will get answer as 4.473 Mbps (dont do any approximation like 2^20 = 10^6 )

Comments

with wrap around time we can get maximum bandwith = 34.13 MBps or 273 Mbps

Taking sequence number = 32 bits

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i think here the identification no. represent the sequence no. as 

i have learned through https://gateoverflow.in/20900/find-wrap-around-time

Answer 2

In the options, the units are mentioned wrong. The answer will be 35.79 Mb/s or 4.47 MB/s (megabyte per seconds).

In the options its mentioned megabits/seconds which isn’t match with the answer.