first step get the instrcution from memory to instruction register. The time will depend on the size of instruction. In one cycle 1 word will be read from memory. First instruction will take 16 cycle for getting in the Instruction register. Then for indirect addressing 4 cycle to get EA then 4 to get oprand. LIKe wise it will be 24 + 12 + 10 + 2 + 24 + 4 for all instruction respectively.
1 clock = 1/ frequency
total clock required = 76
time = 76/2 ns = 38 ns
