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in CO and Architecture by Loyal (6.8k points) | 156 views

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first step get the instrcution from memory to instruction register. The time will depend on the size of instruction. In one cycle 1 word will be read from memory. First instruction will take 16 cycle for getting in the Instruction register. Then for indirect addressing 4 cycle to get EA then 4 to get oprand. LIKe wise it will be 24 + 12 + 10 + 2 + 24 + 4 for all instruction respectively.

1 clock = 1/ frequency
total clock required = 76

time = 76/2 ns = 38 ns
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