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Suppose the numbers $7, 5, 1, 8, 3, 6, 0, 9, 4, 2$ are inserted in that order into an initially empty binary search tree. The binary search tree uses the usual ordering on natural numbers. What is the in-order traversal sequence of the resultant tree?

  1. $7 \ 5  \ 1 \ 0 \ 3 \ 2 \ 4 \ 6 \ 8 \ 9$

  2. $0 \ 2 \ 4 \ 3 \ 1 \ 6 \ 5  \ 9  \ 8  \ 7$

  3. $0 \ 1 \ 2 \ 3 \ 4 \ 5 \ 6 \ 7 \ 8 \ 9$

  4. $9 \ 8 \ 6 \ 4  \ 2  \ 3 \ 0 \ 1 \ 5 \ 7$

in DS by Veteran (52.2k points)
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2 Answers

+24 votes
Best answer

In-order traversal returns the elements in sorted order.

Therefore, it's option C

by Junior (579 points)
edited by
+1 vote

Inorder traversal

  1. First, visit all the nodes in the left subtree
  2. Then the root node
  3. Visit all the nodes in the right subtree

by (189 points)

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