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Suppose the numbers $7, 5, 1, 8, 3, 6, 0, 9, 4, 2$ are inserted in that order into an initially empty binary search tree. The binary search tree uses the usual ordering on natural numbers. What is the in-order traversal sequence of the resultant tree?

  1. $7 \ 5  \ 1 \ 0 \ 3 \ 2 \ 4 \ 6 \ 8 \ 9$

  2. $0 \ 2 \ 4 \ 3 \ 1 \ 6 \ 5  \ 9  \ 8  \ 7$

  3. $0 \ 1 \ 2 \ 3 \ 4 \ 5 \ 6 \ 7 \ 8 \ 9$

  4. $9 \ 8 \ 6 \ 4  \ 2  \ 3 \ 0 \ 1 \ 5 \ 7$

asked in DS by Veteran (59.7k points)
edited by | 2.1k views

2 Answers

+22 votes
Best answer

In-order traversal returns the elements in sorted order.

Therefore, it's option C

answered by Junior (583 points)
edited by
0 votes

Inorder traversal

  1. First, visit all the nodes in the left subtree
  2. Then the root node
  3. Visit all the nodes in the right subtree

answered by (105 points)
Answer:

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