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Define the value of $r$ in the following: $\sqrt {(41)_{r}} = (7)_{10}$
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$\sqrt{(41)_r} = (7)_{10}$

Squaring both sides we get

$(41)_r = (49)_{10}$

$\implies 4r+1 = 10\times 4+9$

$\implies 4r = 48$

$\implies r = 12$
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