0 votes 0 votes Linear Algebra complex-number + – Proton asked Mar 29, 2015 Proton 504 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 4 votes 4 votes Given equation is $$({\sqrt{8}+i})^{50} = 3^{49}(a+ib)$$ take the conjugate on both sides $$({\sqrt{8}-i})^{50} = 3^{49}(a-ib)$$ After multiplying both equations we will get, $${9}^{50} = 3^{98}(a^2 + b^2)$$ $$ (a^2 + b^2) = 9$$ suraj answered Mar 31, 2015 • selected Mar 31, 2015 by Proton suraj comment Share Follow See 1 comment See all 1 1 comment reply Proton commented Mar 31, 2015 reply Follow Share Nice short solution. I also got the answer but in a lenghty manner(by adjusting the eq,the LHS vector will have a manitude of 1 and then comparing the real and imaginary part of both sides.). Thanks ! 0 votes 0 votes Please log in or register to add a comment.