1 votes 1 votes Probability engineering-mathematics probability + – KISHALAY DAS asked Dec 12, 2016 KISHALAY DAS 694 views answer comment Share Follow See 1 comment See all 1 1 comment reply . commented Dec 13, 2016 reply Follow Share is ans 1/3 ? 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes Let P(R) = Rotten eggs and P(G) = Good eggs. P(R) = 3/7 , P(G1)=4/7 .P(G2)=3/6. $P\left (\frac{G2}{G1} \right ) = P\left (\frac{G2\cap G1}{G1}\right ) = $ 4/7 * 3/6 / 4/7 = 3/6 Ans is 1/2. Prabhanjan_1 answered Dec 13, 2016 Prabhanjan_1 comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments Sanket_ commented Dec 15, 2016 reply Follow Share @ prabhanjan_1 why are you selecting one by one when the question has said that both eggs are taken together. why didn't we do like this P(G2/G1) P(G2$\cap$G1)= $_{2}^{4}\textrm{C}$/$_{2}^{7}\textrm{C}$ P(G1)=( $_{2}^{4}\textrm{C}$ +$_{1}^{3}\textrm{C}$.$_{1}^{4}\textrm{C}$ ) / $_{2}^{7}\textrm{C}$ this will give 1/3. 0 votes 0 votes Prabhanjan_1 commented Dec 15, 2016 reply Follow Share Ok taking like that you will get P(G1) = Drawing a good egg = 4C1 / 7C1 = 4/7 --- 1 P(G2∩G1)= Drawing two good eggs = 4C2 / 7C2 = 2/7.---2 So, (2) / (1) => 2/7 / 4/7 = 1/2. 0 votes 0 votes Sushant Gokhale commented Dec 23, 2016 reply Follow Share The probablity is 1/3 {good, good}, {good, bad}, {bad,good} Only 1st qualifies. So, 1/3. 2 votes 2 votes Please log in or register to add a comment.
0 votes 0 votes see total 7 eggs. of which 4 are good and 3 rotten. now given 2 eggs are taken out together in which one is good. so obvious that good one must have been taken from 4 eggs which are good. so now remains only 3 good eggs and 3 rotten eggs. now the question is asking what is the probability of 2nd egg to be good. clearly, it is 3/6=1/2=0.5 Rajesh Raj answered Dec 15, 2016 Rajesh Raj comment Share Follow See all 0 reply Please log in or register to add a comment.