Bias value determination

Question

What would be the bias value for

a. A base-2 exponent in a 6-bit field?

 b. A base-8 exponent in a 7-bit field?

Comments

For a ) since exponent is 6 bit field then bias value is 2^(6-1) -1 = 31=011111(Base2 )

And for b ) Since exponent is a 7 bit field = 2^(7-1)-1=63=0000077 (Base 8 )

Am i right ??

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base value only for representing no..
u r right ..

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@Digvijay Pandey I am not able to understand this one. Can you please explain this in depth.   Thank you

Answer 1

I assume that the exponent value is represented as 2's complement.

the bias value is a number which will be added to actual exponent to make the n-bit exponent to lie in the range (0 to 2ⁿ - 1).

i.e., for 8 bits, the exponent shall be from 0 to 255.

Since the actual range of 8 bit signed integers is -128 to +127, we need to add +128 to exponent to bring the range to 0 to +255. So +128 is the bias value for 8 bit exponent.

In similar way,

1) for 6 bits, the actual range is -32 to +31. so bias value is +32.

2) for 7 bits, the actual range is -64 to +63. so bias value is +64. in base-8, 080.