2 votes 2 votes The round trip delay between X and Y is given as 60 ms and bottle neck bandwidth of link between X and Y is 512 KBps. What is the optimal window size (in packets) if the packet size is 64 bytes and channel is full duplex thor asked Dec 15, 2016 thor 1.8k views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Show 3 previous comments thor commented Dec 15, 2016 reply Follow Share You sure about it. Does using full duplex affect it anyway? 0 votes 0 votes Rajesh Raj commented Dec 15, 2016 reply Follow Share window size =(1+2a) where a =Tp/Tt so it comes 481 bits 0 votes 0 votes santhoshdevulapally commented Dec 16, 2016 reply Follow Share @Rajesh,dont use formula 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes it is 240 packets only. if the link is half duplex then in 1 rtt you will be able to send 1 window. but if link is full duplex you can send 2 windows in 1 rtt. so 2 windows size will become 60*512B. so number of packets per window will be 240 balagangadhar12 answered Dec 26, 2016 balagangadhar12 comment Share Follow See 1 comment See all 1 1 comment reply soumyagupta commented May 6, 2021 reply Follow Share Why in full duplex we can send 2 Windows in RTT 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes first find the bandwidth delay product = bandwidth * RTT = 512KBps * 60ms = 30720B. If the size of the each packet is 64B. then total no of packets = 30720B/64B = 480 packets. IT is given wrong in made easy workbook ankitron answered May 10, 2019 ankitron comment Share Follow See all 0 reply Please log in or register to add a comment.