1,306 views

1 Answer

1 votes
1 votes

Logical Address :

Outer Page (P1) {13-bits} Inner Page(P2) {14-bits} Page offset(d) {12-bits}

Physical Address :

Frame Number (f) {27-12=15-bits} Frame offset(d) {12-bits}

Inner page table Size = 2P∗ Inner page table entry size = 214 * 64 bits = 214 * 8 bytes = 128 KB.

Outer page table Size = 2P∗ Outer page table entry size = 213 * 32 bits = 213 * 4 bytes = 32 KB

So, The inner Page table size is 128 KB and outer page table size is 32 KB.

edited by

Related questions

1 votes
1 votes
2 answers
2
ajayraho asked Oct 29, 2022
634 views
Is the page table entry size same for each entry in page tables of all levels in multilevel paging?
0 votes
0 votes
1 answer
4
Markzuck asked Dec 22, 2018
1,326 views
for memory overhead in Multi level paging, for innermost table only 1 page size shall be counted na? and NOT the complete page table size?please explain the concept, than...