0 votes 0 votes I got the ans as 1/(5*25) = 1/125. None of the, match Digital Logic digital-logic clock-frequency digital-counter + – prasitamukherjee asked Dec 18, 2016 • retagged Aug 4, 2017 by Arjun prasitamukherjee 675 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Ans is (1/(5*25ns)= (1000/125)MHz = 4MHz Note that Time is in nanosecond. Anup patel answered Dec 31, 2016 Anup patel comment Share Follow See 1 comment See all 1 1 comment reply prasitamukherjee commented Jan 5, 2017 reply Follow Share 1000/125 is 8 not 4 6 votes 6 votes Please log in or register to add a comment.
0 votes 0 votes Delay of 5 multiplexer and a feedback loop will be (5+5) X 25 =250 1000/250 =4 MHz Neeraj Chandrakar answered Jul 23, 2017 Neeraj Chandrakar comment Share Follow See 1 comment See all 1 1 comment reply HeartBleed commented Nov 14, 2019 reply Follow Share Nothing has been told about the feedback delay. How you calculated it? 0 votes 0 votes Please log in or register to add a comment.