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1.How many minterms are there in 3 variable boolean operation?

is it 2^n?If yes then how is true?

2.How many prime implicants are in cyclic prime implicant kmap?

Answer given was:- Number of minterms

Is it number of minterms or no. of minterms which are 1?In either case ,ways please explain

in Digital Logic by Boss (25.3k points)
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1 Answer

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K map f(ABC ) = (0 2 3 4 5 7) does not have any essential prime implicate all are prime implicate show answer will be 2 because here two different groups are there.
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