$\text{ABRACADABRA}$
$A\rightarrow 5\\ B\rightarrow 2\\ R\rightarrow 2$
Total Permutation of words $={11!}$
Now,we have to remove word from total permutation of words which have repetition of letter,
$=\dfrac{11!}{5!2!2!}$
Hence option A) is correct.