0 votes 0 votes An EX-OR gate with six variables is as follows Y=A⊕B⊕C⊕D⊕E⊕F The number of min terms in the Boolean expression is_____ Digital Logic digital-logic + – gautamcse27 asked Dec 22, 2016 gautamcse27 1.9k views answer comment Share Follow See 1 comment See all 1 1 comment reply Anusha Motamarri commented Dec 22, 2016 reply Follow Share 32 as xor gives 1 for odd number of 1's in input 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes $F = A \oplus B$, Minterms $ = 2$ $F = A \oplus B \oplus C$, Minterms $ = 4$ So, for XOR of n variables, Minterms $ = 2^{n-1}$ For $Y=A⊕B⊕C⊕D⊕E⊕F$, Minterms $= 2^5 = 32 $ mcjoshi answered Dec 22, 2016 edited Feb 23, 2017 by mcjoshi mcjoshi comment Share Follow See 1 comment See all 1 1 comment reply thor commented Dec 29, 2016 i edited by thor Dec 29, 2016 reply Follow Share does it always holds ? 0 votes 0 votes Please log in or register to add a comment.