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An EX-OR gate with six variables is as follows Y=A⊕B⊕C⊕D⊕E⊕F The number of min terms in the Boolean expression is_____

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$F = A \oplus B$, Minterms $ = 2$

$F = A \oplus B \oplus C$, Minterms $ = 4$

So, for XOR of n variables, Minterms $ = 2^{n-1}$

For $Y=A⊕B⊕C⊕D⊕E⊕F$, Minterms $= 2^5 = 32 $
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