find the time complexity

Question

Consider the following function

int foo(int n) {
    int count1=0, count2=0;
    if (n < 0) n = -n;
    if (n == 0) return 1;
    If (n == 1) return 0;
    while (n) {
        if (n & 1) count1++;
        n = n >> 1;
        if (n & 1) count2++;
        n = n>>1;
    }
    return foo(abs(count1 - count2));
}

What is the time complexity for the above function?

Comments

if the number is n = $01010101010101010101$.in binary.etc..something...abs(coont1-count2) $\approx$ $\log_2 \sqrt{n}$..

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even if you take n= 0101010101 suppose,

then after 5 iterations count1 will be 5 but count 2 will be 4 only because in last iteration,n became 0 before 

if (n & 1) count2++;

so count2++ did nt get exceute.

thn it exits while loop.and abs(count1 -count2 ) =1

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why are you incrementing count2...even after taking that sequence of bits ??