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Best answer
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$f = D.\overline{A}.\overline{B}C + 1.\overline{A}.B.\overline{C} + D.A.\overline{B}.\overline{C} + D.A\overline{B}C + 1.AB\overline{C}$

$f = \overline{A}.\overline{B}CD + (D + \overline{D})\overline{A}.B.\overline{C} + A.\overline{B}.\overline{C}D + A\overline{B}CD + AB\overline{C}(D+\overline{D})$

$f = \overline{A}.\overline{B}CD + \overline{A}.B.\overline{C}D + \overline{A}.B.\overline{C}.\overline{D} + A.\overline{B}.\overline{C}D + A\overline{B}CD + AB\overline{C}D + AB\overline{C}.\overline{D}$

$f = \sum(3,5,4,9,11,13,12)$

Hence, Option (D) is correct.
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ans is d.


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