equivalence relation

Question

Answer 1

Ans B)

In transitive closer we know (x,y),(y,z),then (x,z)

Now,(x,y), where y=x+1

(y,z) could be z=y+1=x+2

that is not in range 0<x<2

In T

It is  satisfying reflexive,symmetric and transitive property.

(x,y),x-y is an integer

and  range of integer $-\alpha to +\alpha$

So, T is equivalence relation

Comments

S isnt even reflexive

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yep, that is true